ONE MARK QUESTIONS
Q.1.Neutrons can be found in all atomic nuclei except in one case. Which is this atomic nucleus and what does it consists of?
Ans. Hydrogen atom. It consists of only one proton.
Q.2. Calculate wave number of yellow radiations having wavelength of 5800 A0.
Ans. Wave number = 1/ wavelength Wavelength = 5800 A0= 5800 x 10-10 m
Wave number = 1/5800 x 10-10 m = 1.72 x 106 m-1
Q.3. What are the values of n and l for 2p orbital?
Ans. n=2 and l= 1
Q.4. Which of the following orbitals are not possible?
Ans. 1p, 2s, 3f and 4d Ans. 1p and 3f are not possible.
Q.5. Write the electronic configuration of the element having atomic number 24.
Ans. 1s2 2s2 2p6 3s2 3p6 3d5 4s1
Q.6. What atoms are indicated by the following electronic configurations?
Ans. a. 1s2 2s2 2p1 b. [Ar]4s2 3d1
a. Boron b. Scandium
Q.7. What is the relationship between frequency and wavelength of light?
Ans. velocity of light = frequency x wavelength. Frequency and wavelength are inversely proportional to each other.
Q.8. State Pauli Exclusion Principle.
Ans. No two electrons in an atom can have the same set of four quantum numbers or an orbital can have maximum two electrons and these must have opposite spin.
Q.9. When α- rays hit a thin foil of gold, very few α- particles is deflected back.
What does it prove?
Ans. There is a very small heavy body present within the atom.
Q.10. What is the difference between a quantum and a photon?
Ans. The smallest packet of energy of any radiation is called a quantum whereas that of light is called photon.
Q.1.Neutrons can be found in all atomic nuclei except in one case. Which is this atomic nucleus and what does it consists of?
Ans. Hydrogen atom. It consists of only one proton.
Q.2. Calculate wave number of yellow radiations having wavelength of 5800 A0.
Ans. Wave number = 1/ wavelength Wavelength = 5800 A0= 5800 x 10-10 m
Wave number = 1/5800 x 10-10 m = 1.72 x 106 m-1
Q.3. What are the values of n and l for 2p orbital?
Ans. n=2 and l= 1
Q.4. Which of the following orbitals are not possible?
Ans. 1p, 2s, 3f and 4d Ans. 1p and 3f are not possible.
Q.5. Write the electronic configuration of the element having atomic number 24.
Ans. 1s2 2s2 2p6 3s2 3p6 3d5 4s1
Q.6. What atoms are indicated by the following electronic configurations?
Ans. a. 1s2 2s2 2p1 b. [Ar]4s2 3d1
a. Boron b. Scandium
Q.7. What is the relationship between frequency and wavelength of light?
Ans. velocity of light = frequency x wavelength. Frequency and wavelength are inversely proportional to each other.
Q.8. State Pauli Exclusion Principle.
Ans. No two electrons in an atom can have the same set of four quantum numbers or an orbital can have maximum two electrons and these must have opposite spin.
Q.9. When α- rays hit a thin foil of gold, very few α- particles is deflected back.
What does it prove?
Ans. There is a very small heavy body present within the atom.
Q.10. What is the difference between a quantum and a photon?
Ans. The smallest packet of energy of any radiation is called a quantum whereas that of light is called photon.
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