Tuesday 18 October 2016

practice equilibrium questions and answers in chemistry

    2

Q.1. Mention the factors that affect equilibrium constant.
  • Answer 1:Temperature, pressure, catalyst and molar concentration of reactants and products.
Q.2. Write relationship between Kp and Kc for the gaseous reaction: N2 + O2 ⇌ 2NO
  • Answer 2: Kp = Kc as Ξ”n is zero for the above said reaction.
Q.3. Write Kc for the gaseous reaction: N2 + 3H2 ⇌ 2NH3
  • Answer 3: Kc = [𝑁𝐻3]2 /[𝑁2] [𝐻2]3
Q.4. What is effect of catalyst on equilibrium constant Kc?
  • Answer 4: A catalyst does not affect equilibrium constant because it speeds up both forward and backward reactions to the same extent.
Q.5. State Le Chatelier’s principle.
  • Answer 5: It states that a change in any of the factors that determine the equilibrium conditions of a system will cause the system to change in such a manner so as to reduce or to counteract the effect of the change.
Q.6. Explain homogeneous and heterogeneous equilibrium giving examples.
  • Answer 6: If all the reactants and products present in an equilibrium mixture are in same phase → homogeneous equilibrium.
    Example: 𝑁2(𝑔) + 3𝐻2 (𝑔) ⇌ 2𝑁𝐻3 (𝑔)
    If all the reactants and products present in an equilibrium mixture are indifferent phase → heterogeneous equilibrium.
    Example: πΆπ‘ŽπΆπ‘‚3 (𝑠) ⇌ πΆπ‘Žπ‘‚(𝑠) +𝐢𝑂2(𝑔)
Q.7. Describe the effect of a) addition of H2
b) addition of CH3OH
c) removal of CO
d) removal of CH3OH on the equilibrium of the reaction: 2H2 (g) + CO (g ) ⇌ CH3OH (g)

  • Answer 7: a) addition of H2 equilibrium will shift on RHS.
    b) addition of CH2OH equilibrium will shift on LHS.
    c) removal of CO equilibrium will shift on LHS.
    d) removal of CH3OH equilibrium will shift on RHS.
Q.8. For the equilibrium, 2NOCl(g) ⇌ 2NO(g) + Cl2(g) the value of the equilibrium constant, Kc is 3.75×10–6 at 1069 K. Calculate the Kp for the reaction at this temperature?
  • Answer 8: We know that, Kp = Kc (RT)Ξ”n
    For the above reaction,
    Ξ”n = (2+1) – 2 = 1
    Using, Kp = Kc (RT)Ξ”n
    Kp = 3.75 ×10–6 (0.0831 × 1069)
    Kp = 0.033.
Q.9. Hydrolysis of sucrose gives, Sucrose + H2O → Glucose + Fructose
Equilibrium constant Kc for the reaction is 2 × 1013 at 300 K. Calculate Ξ”G0 at 300 K.

  • Answer 9: Ξ”G0 = – RT lnKc
    Ξ”G0 = – 8.314 × 300 × ln( 2×1013 )
    Ξ”G0 = – 7.64 ×104 J/mol.
Q.10. At 473 K, equilibrium constant Kc for decomposition of phosphorus pentachloride, PCl5 is 8.3 ×10–3.
If decomposition is depicted as, PCl5 (g) ⇌ PCl3(g) + Cl2 (g) Ξ”rH0 = 124.0 kJ mol–1
a) Write an expression for Kc for the reaction.
b) What is the value of Kc for the reverse reaction at the same temperature?
c) What would be the effect on Kc if
(i) more PCl5is added
(ii) pressure is increased
(iii) the temperature is increased ?

  • Answer 10: a) 𝐾c=[𝑃𝐢𝑙3][𝐢𝑙2][𝑃𝐢𝑙5] b) 120.48 c) (i) equilibrium will shift on RHS.
    (ii) equilibrium will shift on LHS.
    (iii) equilibrium will shift on RHS.
Q.11. Dihydrogen gas is obtained from natural gas by partial oxidation with steam As per following endothermic reaction:
CH4 (g) + H2O (g) ⇌ CO (g) + 3H2 (g)
(a) Write as expression for Kp for the above reaction.
(b) How will the values of Kp and composition of equilibrium mixture be Affected by
(i) increasing the pressure
(ii) increasing the temperature
(iii) using a catalyst?

  • Answer 11: (a) 𝐾𝑝=[𝐢𝑂][𝐻2]3/[𝐢𝐻4][𝐻2𝑂]
    (b) (i) Value of Kp will not change, equilibrium will shift in backward direction.
    (ii) Value of Kp will increase and reaction will proceed in forward direction.
    (iii) No effect.

equilibrium questions and answers chemistry

2 comments:
Write comments

Copyright (c) 2019 to 2020 - Chemistry Education Zone - All Right Reseved

© 2018 - 2020 Chemistry Education Zone. Designed by Bloggertheme9 | Distributed By Gooyaabi Templates
.
close